What us the equation of the line shown in this graph (-4,1) (2'1)

y=1

Step-by-step explanation:

we know that the equation of the line is:

y=mx+b

m= slope= (y2-y1)/(x2-x1)

we have two points giver from the graph:

point 1: (-4,1)

point 2: (2,1)

we to find the slope:

m=(1-1)/(2-(-4))

so we have m=0

we need to find "b"

using the point (2,1)

we have:

1=0x+b

so we have b=1

finally we have

y=0x+1

so  y =1