Which values of p and qresult in an equation with no solutions? -60x+32=qx+p

Q is -60 and P is -32

Step-by-step explanation:

values of P and Q result in an equation with no solutions

When an equation have a no solution only when there is no x and both sides of equation are not same.

To eliminate x both sides of 'x' terms should be same

So Qx should be -60x

the value of Q= -60

To make both sides unequal , the value of p should be some other number

or opposite of 32

so p = -32

Add 60x on both sides

not same, its false

So , the equation has no solution

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

55/i dont know i do it for the points

step-by-step explanation: