What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6 ? enter your answer in the box

y=2/3x-9

Step-by-step Explanation

1.You put 2x-3y=6 into y-intercept to find out the slop, which is 2/3.

2. Put the coordinate pair given into point slop form, which will look like this: y+3=2/3(x-9)

3. Put that into y-intercept (answer)

4. Boom done

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5