Old mcdonald purchased a pool with a capacity 100 gallons for his farm. one day, at 1: 00 p. m., he placed a hose onto the pool which filled it with water at a rate of 5 gal per hour. after 10 hours, horses and cows started drinking the water at a rate of 2 gal/hr. five hours after that, mr. mcdonald noticed the animals and placed a second hose in the pool which filled it at a rate of 4 gal/hr. when did mr. mcdonald have himself a pool full of water?

Based on the fill rate, discharge rate and time given, the pond should be filled up by 9:00 a.m the next morning.

Initial filling rate = 5 gallons per hour

Amount of water in pool after 10 hours:

Filling rate × time

Amount of water in pool after 10 hours = 5 × 10 = 50 gallons

Discharge rate after 10 hours = 2 gallons per hour

Net filling rate = 5 gal/hr - 2gal/hr = 3 gal/hr

Amount of water filled into the po at this rate after 5 hours :

3 gal/hr × 5 hr = 15 gallons

Additional recharge = 4 gal/ hr

Amount of Gallons left = 100 - (50 + 15) = 35 gallons

Number of hours till full = (gallons left) ÷ fill rate

Number of hours left = (35 ÷ 7) = 5 hours

Hence, the pool will be full after (10 + 5 + 5) = 20 hours

Therefore, the pond will be full at 9:00 am the next day.

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step-by-step explanation:

circumference divided by 3.141592654 then timesthe radius twice

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90