Sq bisects rst, and rsq = 2x-4. write an expression for rst. slect an 4x – 8 4x – 4 2x – 4 x – 2

4x - 8

Step-by-step explanation:

... ∠RST = ∠RSQ + ∠QST

Since SQ bisects ∠RST, that means ...

... ∠RSQ = ∠QST

Using this fact in the first equation, we have

... ∠RST = ∠RSQ + ∠RSQ = 2×∠RSQ

Using the given expression for ∠RSQ, we have

... ∠RST = 2×(2x-4) = 4x - 8

4x - 8 ← first in list

Since SQ bisects ∠RST then ∠RSQ = ∠QST = 2x - 4

∠RST = ∠RST + ∠QST

∠RST = 2x - 4 + 2x - 4 = 4x - 8

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: