Given the system of equations presented here: 3x + 5y = 29 x + 4y = 16 which of the following actions creates an equivalent system such that, when combined with the other equation, one of the variables is eliminated? a) multiply the second equation by −1 to get −x − 4y = −16 b) multiply the second equation by −3 to get −3x − 12y = −48 c) multiply the first equation by −1 to get −3x − 5y = −29 d) multiply the first equation by −3 to get −9x − 15y = −87

ANSWER

The correct answer is option B

EXPLANATION

The equations are

and

When we multiply the second equation by , we obtain;

When we combine this new equation with equation (1).

We can see that has been eliminated from the equation.

We can then, solve for   and then substitute the result in to any of the equations to find .

Hence the correct answer is option B

B) Multiply the second equation by −3 to get −3x − 12y = −48

Step-by-step explanation:

We are given two equations:

--- (i)

--- (ii)

If we multiply the second equation by -3, we get:

--- (iii)

Combining equation (i) and (iii) to get:

3x and -3x cancel each other so x is eliminated and we are left with:

Therefore, the correct answer option is B) Multiply the second equation by −3 to get −3x − 12y = −48.

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation: