Ahot-air balloon is 150 ft above the ground when a motorcycle (traveling in a straight line on a horizontal road) passes directly beneath it going 40 mi/hr (58.67 ft/s). if the balloon rises vertically at a rate of 10 ft/s, what is the rate of change of the distance between the motorcycle and the balloon 10 seconds later?

Answer-

Rate of change of the distance between the motorcycle and the balloon after 10 seconds is 57.89 ft/s.

Solution-

Let's consider an instance after t second,

Let D = Distance between the motorcycle and hot air balloon

As shown in the attachment, the situation represents a right angle triangle, hence applying Pythagoras Theorem,

After t=10 seconds,

Then, rate of change of the distance between the motorcycle and the balloon after 10 seconds will be,

i'm sorry i don't know

step-by-step explanation:

i believe that the slope of the line is -5

step-by-step explanation: