Points a, b,c, d, and e are collinear and in that order. find ac if ae = x+50 and ce = x+32.

                             AC= 18

It is given that:

Points A,B,C,D, and E are collinear and in that order.

AE = x+50 and CE = x+32.

Now, we know that the length of the line segment AC is equal to the length of the line segment AE minus the length of the line segment CE.

i.e.

AC=AE-CE

i.e.

AC= x+50-(x+32)

AC=x+50-x-32

( Since if the sign before the parentheses is negative then the terms comes out of the parentheses with a opposite sign )

Hence, on combining the like terms we have:

AC=x-x+50-32

AC=0+18

Hence, we get:

               AC= 18

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: