Arectangular parking lot has length that is 9 yards less than twice its width. if the area of the land is 221 square yards, what are the dimensions of the land?

The width is 13, the length is 17

Step-by-step explanation:

You have to write an expression to represent the area of the rectangle. The width can be w, and the length can be 2w-9. Since the parking lot is a rectangle, you multiply the length by the width to get your area. w(2w-9) is 2w^2-9w=221. The only value of w that satisfies this equation when substituted is 13, so that is your width. 2(13)-9 is 26-9 is 17, so the length is 17.

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

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