Give the equation of a line through the points (8,2) and (0,6).

The equation of a line through the points (8,2) and (0,6).

y= -1/2x+6

in case u need to understand it
(8,2) and (0,6).
First of all, remember what the equation of a line is:

y = mx+b
Where:
m is the slope, and
b is the y-intercept
First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.
For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (8,2), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=8 and y1=2.
Also, let's call the second point you gave, (0,6), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=0 and y2=6.

Now, just plug the numbers into the formula for m above, like this:

m=
6 - 2
0 - 8
or...

m=
4
-8
or...

m=-1/2
So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-1/2x+b
Now, what about b, the y-intercept?
To find b, think about what your (x,y) points mean:
(8,2). When x of the line is 8, y of the line must be 2.
(0,6). When x of the line is 0, y of the line must be 6.
Because you said the line passes through each one of these two points, right?
Now, look at our line's equation so far: y=-1/2x+b. b is what we want, the -1/2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (8,2) and (0,6).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(8,2). y=mx+b or 2=-1/2 × 8+b, or solving for b: b=2-(-1/2)(8). b=6.
(0,6). y=mx+b or 6=-1/2 × 0+b, or solving for b: b=6-(-1/2)(0). b=6.
See! In both cases we got the same value for b. And this completes our problem.
The equation of the line that passes through the points
(8,2) and (0,6)

is

y=-1/2x+6