Write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (-4,8); y=1/4x -4

so, here we have  a line that is perpendicular to a the line 1/4x -4and we are asked for the perpendicular line which passes through the point (-4,8)

Step-by-step explanation:

1. calculate perpendicular line (i.e. at 90 degrees to the line)

2. m1 x m2 = -1 where slope is m. and m1 = 1/4 (from the original equation)

1/4 x m2 = -1 , therefore m2 = -1/(1/4) = -1 x (4/1) = -4

3. therefore the equation is : y= -4x - 4

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204