Write the equation of a line perpendicular to y = -5/6x -3 and whose y-intercept is (0,11). i fr need ..

Hey!

A perpendicular line has the slope as the negative reciprocal of the given line, so therefore the new lines slope would be...

y = 6/5x + b

Now to find the y-intercept you will have to just plug in the given point/coordinate in the equation above and solve for b...

11 = 6/5(0) = b

11 = b

Put the given slope and y-intercept in a slope intercept form equation (slope intercept form is y = mx + b)...

y = 6/5x + 11

This new equation is:

1) perpendicular to the given equation

2) in slope intercept form

y = 6/5x + 11

Hope this Helped!

~A

step-by-step explanation:

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1