Point q is a point on the side bc of a parallelogram abcd. point m is on aq so that 2am=3qm. ratio area of dmq : area of abcd is equal to: (a) 1/6 (b) 1/5 (c) 1/10 (d) 2/5

Consider ΔAQD. This triangle has the area

where H is the heigh drawn from the point Q to the side AD.

Note that the height H is also the height of the parallelogram. So the area of the parallelogram ABCD is

From these two statements you can conclude that

Now consider ΔDMQ. The ratio  between  the area of triangles DMQ and AQD is

Since you have that

and

Thus,

correct choice is B