Find 3 consecutive odd integers such that twice the sum of the first and third exceeds the second by fifteen

The three consecutive odd integers are 3,5,7

How:

Let x, (x+2),(x+4) represent the three consecutive odd integers

Question states***  

2[x + (x+4)] = (x+2) + 15

solving for s

  4x + 8 = x + 17

    3x = 9

     x = 3   The three consecutive odd integers are 3,5,7

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step-by-step explanation:

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times