It takes tyler twice as long as kyle to complete the same job. when the men work together, they can complete the job in 6 hours. how many hours are required for tyler to do the job alone? enter your answer in the box.

Time taken by Tyler to do the job alone =18 days.

Explanation:

Since we have given that

Tyler takes twice as long as Kyle to complete the same job,

Let the work done by Kyle in 1 day be

Let the work done by Tyler in 1 day

If the men work together , they can complete the work in 6 hours.

According to question, we get

Hence, time taken by Kyle is x= 9 hours

and

Time taken by Tyler to do the job alone is given by

Answer

Tyler to do the job alone =18/1 = 18 hrs

Solution

It takes Tyler twice as long as Kyle to complete the same job.

efficiency of Kyle  is twice the efficiency of Tyler  

Let x be the efficiency of Tyler the efficiency of Kyle is 2x

efficiency of Tyler  : efficiency of Tyler = x :2x =1:2

Therefore total efficiency = 1 + 2 =3x

The total job = efficiency x total time

Here total time to complete the job=6 hrs

Total job =18

Time taken to complete the job =Total job/efficiency

Tyler to do the job alone =18/1 = 18 hrs

Kyle to do the job alone =18/2 = 9 hrs

two data sets with the same median will not have the same varaibility

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph