Aboat travels 12 km upstream and back in 1 hour 45 minutes. if the speed of the current is 3 km/h throughout, find the speed of the boat in still water, giving your answer correct to 3 significant figures.

14.3 km/h   to 3 significant figures

Step-by-step explanation:

Let time travelling upstream be t1 hours and downstream = t2 hours.

t1 + t2 = 1.75(1)

Let v  be the speed of the boat in still water.

12 / t1 = v - 3(2)

12 /  t2 = v + 3(3)

From (1) and (3) , substituting for t2:-

12 / (1.75 - t1) = v + 3 (4)

Subtract:-   (2) - (4):-

12 / t1 - 12 / (1.75 - t1) = -6

12(1 .75 - t1) - 12t1 = -6t1(1.75 -  t1)

21 - 12t1 - 12t1 = -10.5t1 + 6t^2

6t1^2 + 13.5t1 - 21 = 0

Solving this gives t1 = 1.058 hours

Therefore the speed in still water (v)  = 12/1.058 + 3 = 14.3 to 3 sig figs

the answer is d. (1.2, -4.7) on edgn

hope this !