Which expression has a value less than the given expression when x = 5? 3x + 15 2x² x² + 5 3(x + 5) 4x + 5

Put the value of x = 5 to the expression:

3x + 15 → 3(5) + 15 = 15 + 15 = 30

2x² → 2(5)² = 2(25) = 50 > 30

x² + 5 → 5² + 5 = 25 + 5 = 30

3(x + 5) → 3(5 + 5) = 3(10) = 30

4x + 5 → 4(5) + 5 = 20 + 5 = 25 < 30

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.

1 ?

step-by-step explanation:

u said 1+1+1+1+1+1+1+1+1+1+1+1*0 so ur adding 1 but then multiplying by 0 so its 0 but then u said 1*0+1 so now ur adding 1 so the answer is juan ?

~leah