Aregular nonagon has a side length of 3 √10 feet. a similar nonagon has a side length of 5 feet. what is the ratio of the first nonagon's perimeter to the second nonagon's perimeter? what is the ratio of the first nonagon's area to the second nonagon's area? a. perimeters = 3√2 areas = 36 c. perimeters = 3√10/5 areas = 90/25 b. perimeters = 5/3√10 areas = 25/90 d. perimeters = 6√10/10 areas = 36/100

If m∠abc = 70°, what is m∠abd? justify your reasoning.  using the addition property of equality, 40 + 70 = 110, so m∠abd = 110°.  using the subtraction property of equality, 70 − 30 = 40, so m∠abd = 30°.  using the angle addition postulate, 40 + m∠abd = 70. so, m∠abd = 30° using the subtraction property of equality.  using the angle addition postulate, 40 + 70 = m∠abd. so, m∠abd = 110° using the addition property of equality.