Suppose you bought eight oranges and on grapefruit for a total of $4.60. later that day, you bought six oranges and three grapefruits for a total of $4.80. now you want to find the price of each orange and of each grapefruit. write an equation for each purchase. solve the system of equations. use process of elimination. show all your work!

8*  oranges + 1 graperfuit = 4.60

6* oranges + 3 grapefruit = 4.80

multiply the first equation by 3

24 oranges + 3 grapefruit = 13.8

subtract the 2nd equation

24 oranges + 3 grapefruit = 13.8

-6* oranges + 3 grapefruit = 4.80

18 oranges = 9

oranges = .50

6 oranges + 3 grapefruit = 4.80

6 * .5 + 3 grapefruit = 4.80

3 + 3 grapefruit = 4.80

subtract 3 from each side

3 grapefruit = 1.80

grapefruit = .60

oranges  $ .50

grapefruit = $.60

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)