Mathematics, 02.07.2019 11:30 Savageboyn

Solve these with the full explained answer and you will get brainliest and 50 but hurry

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Answer from: xXCoryxKenshinXx

ANSWER TO QUESTION 1

The given equation is

4x+10=-26

We add the additive inverse of which is to both sides of the equation to obtain,

4x+10+-10=-26+-10

This gives us,

4x+10-10=-26-10

4x+0=-36

This further simplifies to

4x=-36

We divide both sides to obtain,

x=-4

ANSWER TO QUESTION 2

Since we got as answer to question one, the next question to answer is

$\frac{x}{3}+10=15$

We add the additive inverse of which is to both sides to obtain,

$\frac{x}{3}+10+-10=15+-10$

This gives us,

$\frac{x}{3}+10-10=15-10$

This simplifies to

$\frac{x}{3}+0=5$

$\frac{x}{3}=5$

We now multiply both sides of the equation by to obtain,

$3\times \frac{x}{3}=5\times3$

This implies that,

x=15

ANSWER TO QUESTION 3

The next equation is 9-2x=35

We add the additive inverse of which is to both sides of the equation to obtain,

9+-9-2x=35+-9

This gives us,

9-9-2x=35-9

This simplifies to,

-2x=26

We multiply both sides by the reciprocal or the multiplicative inverse of to obtain,

$-2x\times (-\frac{1}{2})=26\times(-\frac{1}{2})$

This gives us,

x=-13

ANSWER TO QUESTION 4.

The next question is $\frac{2}{3}x+15=17$

We add the additive inverse of 15 to both sides of the equation to obtain,

$\frac{2}{3}x+15+-15=17+-15$

This evaluates to

$\frac{2}{3}x+0=17-15$

This implies that,

$\frac{2}{3}x=2$

We multiply both sides by the multiplicative inverse or the reciprocal of $\frac{2}{3}$

This implies that,

$x=2\times\frac{3}{2}$

x=3

ANSWER TO QUESTION 5

The next question to answer is -5x-10=10 .

We add the additive inverse of which is to both sides of the equation to obtain,

-5x-10+10=10+10

This gives us,

-5x=20

We through by to obtain,

x=-4

ANSWER TO QUESTION 6

$\frac{3}{4}x-9=27$

We add the additive inverse of which is to both sides of the equation to obtain,

$\frac{3}{4}x-9+9=27+9$

This simplifies to;

$\frac{3}{4}x=36$

We multiply both sides of the equation by the reciprocal of $\frac{3}{4}$ to obtain,

$\frac{3}{4}x \times \frac{4}{3}=36\times \frac{4}{3}$

$x=36\times \frac{4}{3}$

$x=12\times 4$

x=48

ANSWER TO QUESTION 7

The next question to answer is $\frac{1}{2}x+13=9$ .

We add the additive inverse of which is to both sides of the equation to obtain,

$\frac{1}{2}x+13+-13=9+-13$

This will evaluate to,

$\frac{1}{2}x=-4$

We now multiply both sides of the equation by to obtain,

$x=-4\times 2$

x=-8

ANSWER TO QUESTION 8

The last question to solve now is $\frac{x-7}{4}=-2$

We first of all multiply both sides of the equation by to obtain,

$\frac{x-7}{4} \times 4=-2\times 4$

This implies that,

x-7=-8

We now add the additive inverse of which is 7 to both sides of the equation to obtain,

x-7+7=-8+7

This implies that

x=-1

Answer from: Quest

answer: finding the extract measurements and knowing the points

step-by-step explanation:

Answer from: Quest

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that runner b is moving at a slower rate."

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