Acatering service offers 7 appetizers, 3 main courses, and 5 desserts. a customer is to select 4 appetizers, 2 main courses, and 4 desserts for a banquet. in how many ways can this be done?

This question is based on combinations

Out of 7 appetizers, 4 are to be selected, this becomes = 7C4

Out of 3 main courses, 2 are to be selected , this is = 3C2

Out of 5 desserts, 4 are to be selected, this is = 5C4

So, total ways become =

7C4 * 3C2 * 5C4

7!/4!(7-4)! * 3!/2!(3-2)! * 5!/4!(5-4)!

= 35*3*5 =525 ways

Hence, this can be done in 525 ways.

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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answer: 0.26

i used the calculator on google