What wpuld be the area of an actual pool be of the scale from the drawing is 3: 1000? 15 cm7.5 will mark brainest

The scale from the drawing means ...

... drawing size : life size = 3 : 1000

This can be turned around to get ...

... life size : drawing size = 1000 : 3

I find this form more convenient to use in a proportion:

... actual length / drawing length = 1000 / 3

Multiplying by "drawing length", we get ...

... actual length = (drawing length)·(1000/3)

This will be true for both drawing lengths.

... Pool length = (15 cm)·1000/3 = 5000 cm = 50 m

... Pool width = (7.5 cm)·(1000/3) = 2500 cm = 25 m

The area is the product of these dimensions:

... pool area = (50 m)·(25 m) = 1250 m²

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17