Draw a polygon with the given conditions in a coordinate plane of rectangle with a perimeter of 20 units

Question says to draw a polygon with the given conditions in a coordinate plane. It is talking about Rectangle with perimeter of 20 units.

So we can use formula of perimeter of rectangel to find it's possible dimensions.

We knwo that perimeter of the rectangle is given by 2(L+W)

where L is lenght and W is width.

Given perimeter is 20 so we get:

2(L+W)=20

L+W=10

L=10-W

So basically we can use any number for W which can be from 0 to 10 as side length can't be negative.

Let W=4

Then L=10-W=10-4=6

Hence we just have to draw a rectangle having length 6 and width 4.

So the final answer will be picture in the attached graph.

where r the answers

step-by-step explanation:

when rotating a figure 180 degrees, imagine that you are able to take the figure and turn it clockwise or counterclockwise around a center point. to rotate a figure 180 degrees, you will need to apply the rule (x, y) → (-x, -y). start by using a coordinate grid with coordinates for each vertex of the figure. the center point of the coordinate grid is located at (0, 0), which is what you will rotate the figure around. write down the original coordinates of the shape you are going to rotate. then, apply the rule. for example, coordinate (1, 2) becomes (-1, -2). another example would be, coordinate (-4, -2) becoming (4, 2). after you change each original coordinate to the rotated coordinate, you will draw your new figure.

step-by-step explanation: