Someone me solve this problem! if you’re smart you can solve it!

let's notate it with letters to I can notate it in this problem

the plus is P

the circle is C

the square is S

the smiley face is F (for face)

the triangle is T

in all, we see that:

circle can't be next to the smiley face or the triangle or the square so it must be at the end next to to the plus sign but we don't know if it is at the right end or the left (P C or C P)

plus is not next to smiley face or triangle, so it must be next to the square (___S P C or C P S___)

triangle is to the right of the square, so we have to choose the guess that has an empty space to the right of the square, so it has to be C P S T __

then the last shape is the smiley face which goes in the last space

so the order is C P S T F or circle, plus, square, triangle smiley face

16

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)