State the vertex and axis of symmetry of the graph of y=ax2+c. the vertex is ( , ) the axis of symmetry is x=

State the vertex and axis of symmetry of the graph of y=ax^2+c

General form of quadratic equation is

There is no bx in our given equation, so we put 0x

Given equation can be written as

a=a , b=0

Now we use formula to find vertex

Now we plug in 0 for 'a' and find out y

So our vertex is (0,c)

The axis of symmetry at x coordinate of vertex

So x=0 is our axis of symmetry

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3