Whlch set of numbers contains both solutions to the equation x2 - 2x - 8 = 0?

x = {-2, 4}

Step-by-step explanation:

0 = x² - 2x - 8

                    ∧

                 1    -8 = -7

                 2   -4  = -2  This works because the b-value is -2!

0 = (x + 2)(x - 4)

0 = x + 2       0 = x - 4

  x = -2              x = 4

the answer is c.

for continuous functions, they continue in the same pattern and you have to find that pattern kinda like slope

no, because the sides are not congruent