Approximate the real number solution(s) to the polynomial function f(x) = x3 + 4x2 + x − 6 a. x = −3, x = −1, x = 2 b. x = 3, x = 1, x = −2 c. x = 3, x = −1, x = 2 d. x = −3, x = 1, x = −2

well let see here

From the options, a or c has x = -1, both has x = , so lets check for x = 3

f(3) = (3)^3 + 2(3)^2 - 5(3) - 6 = 27 + 18 - 15 - 6 = 24; x = 3 is not a solution to the polynomial.

Therefore the solutions to the polynomial are x = -3, x = -1, x = 2

kkkll

step-by-step explanation:

kljlklj