Can sombody me with this math problem? the equation is y= 2/3x-3. there are two different questions to this equation: question 1) find y, if x is 9. question 2) find x, if y is -11.

y=2/3y-3

1. y = 2/3 (9)-3   multiply 9 and 2 =18/3

 y=18/3-3 divide 18 and 3 =6

y=6-3 subt. 3

y=3

2.  -11=2/3x - 3

 -11+3 = 2/3 x   add 3 to both sides to cancel -3

 -8=2/3 x  

(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3

-24/2 = x  divide

-12=x

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: