In △abc, point m is the midpoint of ab , point d∈ ac so that ad: dc=2: 5. if aabc=56 yd2, find abmc, aamd, and acmd.

The area of triangle BMC is 28 yd square, the area of AMD is 8 yd square and the area of CMD is 20 yd square.

Explanation:

Given information: M is the midpoint of the side AB. The line MC is the median of the triangle ABC.

A median divides the area of triangle in two equal parts, therefore the area of triangle BMC is half of the area of triangle ABC.

Therefore the area of BMC and AMC is 28 yd square.

Draw a perpendicular on AD from M as shown in the figure.

Therefore the area of AMD is  th part of the area of AMC.

Therefore the area of AMD is 8 yd square.

Therefore the area of CMD is 20 yd square.

5/12, or 5: 12

step-by-step explanation: