Thallium-207 decays exponentially with a half life of 4.5 minutes. if the initial amount of the isotope was 28 grams, how many grams of the isotope will remain after 7 minutes?

Option B

Step-by-step explanation:

Thallium-207 decays exponentially with a half life period = 4.5 minutes.

So the explicit formula of exponential decay can be written as

=

= Amount after decay

= initial amount

n = decay constant

t = time for decay

Since half life of Thallium is 4.5 minutes.

So   =

ln = ln

-0.69314 = -4.5n ln e

4.5 n = = 0.154

Now we have to calculate amount remaining after 7 minutes when initial amount taken is 28 grams from the formula

=

=

grams

Option B is the answer.

Answer : B. 9.53 grams

Thallium-207 decays exponentially with a half life of 4.5 minutes. if the initial amount of the isotope was 28 grams,

The formula for half life is

Final value = initial value (1/2)^(Time /t(half life))

initial amount of the isotope = 28 grams

half life = 4.5 minutes

Time = 7 minutes

Plug in all the values

Final value

A = 28 * 0.34020= 9.52553

9.53 grams of the isotope will remain after 7 minutes

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step-by-step explanation:

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well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation: