Find the zeros of the function g(x) = x^4 - x^3 - 2x^2

set equal to 0

factor out the

what 2 numbers multiply to get -2 and add to get -1? -2 and 1

set each equal to 0

x=0

x-2=0

x=2

x+1=0

x=-1

so the zeroes of the function are at x=-1, 0, 2

sorry, i don't know i just need points, i'm new here. chao

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.