What is the value of f(-2) for the given functionf(x)=3•2^x show your work i've been stuck on this it's for a practice and i can't seem to get the correct answer.

Copy down the given function:

f(x)=3•2^x

Now replace both instances of x with -2:

f(-2) = 3*2^(-2).                                1

Recall that 2^(-2) is the same as = 1/4

                                                      2^2

Therefore, f(-2) = 3*2^(-2) = 3*(1/4) = 3/4

Remember that exponentiation has to be carried out before multiplication.  That's why I did 2^(-2) before multiplying by 3.

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!

let's first notice, the center of the hyperbola is at the origin, since the focus points are equidistantly 3 units away from the origin, that also means that the distance "c" from the center to either focus is 3.

it should also be notable that, the traverse axis for this hyperbola is vertical, or namely over the y-axis and therefore, the positive fraction will be the one with y-variable.

the traverse "a" component or distance from the center to either vertex is not 2, is more than 2, so we can safely put it at √5 ≈ 2.24.