Middletown street and kensington avenue intersect. if middletown street is 5.2 meters wide and kensington avenue is 7.6 meters wide, what is the distance between two opposite corners of the intersection? if necessary, round to the nearest tenth.

The distance between two opposite corners of the intersection is 9.2 meters.

Explanation:

Since we have given that

Width of the Middletown Street = 5.2 m

Width of Kensington Street = 7.6 m

When they intersect each other then we have to find  the distance between two opposite corners of the intersection,

Since they formed a right angled triangle shown in the figure below:

So, we can apply "Pythagorus Theorem"

Hence, the distance between two opposite corners of the intersection is 9.2 meters.

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560