What are the intercepts of the graphed function? a. x-intercept = (–1, 0) y-intercept = (–3, 0) b. x-intercept = (0, –1) y-intercept = (0, –3) c. x-intercept = (0, –1) y-intercept = (–3, 0) d. x-intercept = (–1, 0) y-intercept = (0, –3) quick yo

Answer

D) x-intercept = (–1, 0)

y-intercept = (0, –3)

Step by step explanation

x-intercept is nothing but where the curve cuts the x-axis, in x-axis the value of y is always zero.

Here the curve cuts the x-axis at x = -1, where y value is 0.

Therefore, the x-intercept = (-1, 0)

y-intercept is nothing but where the curve cuts the y-axis, in y-axis the value of x is always zero.

Here the curve/graph cuts the y-axis at y = -3, where x value is 0.

Therefore, the y-intercept = (0, -3)

The answer is

x-intercept = (–1, 0)

y-intercept = (0, –3)

Thank you.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

step-by-step explanation:

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