Mathematics, 01.07.2019 23:00 kukisbae

The number of customers who ate at a fast food restaurant between 1: 00 p. m. and 3: 00 p. m. each day last week are listed here: 55, 37, 52, 50, 33, 46, 53 what's the standard deviation of the data set?

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Answer from: kev485

ANSWER

The standard deviation is 7.8 correct the nearest tenth.

EXPLANATION

The data set given to us is 55,37,52,50,33,46,53 .

The standard deviation of the given data set can be calculated using the formula,

$Standard\:deviation=\sqrt{\frac{(x-\bar X)^2}{n} }$

where $\bar X=\frac{\sum x}{n}$

$\bar X=\frac{55+37+52+50+33+46+53}{7}$

$\bar X=\frac{326}{7}$

$\bar X=46.57$

We now find the standard deviation as follows;

$SD=\sqrt{\frac{ (55-46.57)^2+(37-46.57)^2+(52-46.57)^2+(50-46.57)^2+(33-46.57)^2+(46-46.57)^2+(53-46.57)^2 }{7} }$

$Standard\:deviation=\sqrt{\frac{71.06+91.58+29.48+11.76+184.14+0.32+41.34}{7} }$

$Standard\:deviation=\sqrt{\frac{429.68}{7} }$

$Standard\:deviation=\sqrt{61.38}$

$Standard\:deviation=7.84$

Answer from: ghernadez

Standard deviation of the data set = 7.84

Step-by-step explanation:

To calculate the standard deviation of the data set first we take the mean of the data .

Mean = $\frac{(55+37+52+50+33+46+53)}{7}$

= $\frac{326}{7}$

= 46.57

Now we subtract the mean from data set and square the answer.

55 - 46.57 = 8.43² = 71.06

37 - 46.57 = -9.57² = 91.58

52 - 46.57 = 5.43² = 29.48

50 - 46.57 = 3.43² = 11.76

33 - 46.57 = -13.57² = 184.14

46 - 46.57 = -0.57² = 0.32

53 - 46.57 = 6.43² = 41.34

Then we will take the mean of squared result.

$\frac{(71.06+91.58+29.48+11.76+184.14+0.32+41.34)}{7}$

= $\frc{429.68}{7}$

Variance = 61.38775509

Lastly take the square root of variance

= $\sqrt{61.38775509}$

= 7.835033828 rounded to 7.84

Standard deviation of the data set = 7.84

Answer from: Quest

Look i don’t know the answer to this but someone else will so just wait a little bit longer

Answer from: Quest

a) one student is chosen from classroom a, then a student is chosen from classroom b.

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b. this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes. this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes. this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes. this makes them dependent events.

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