Suppose that g (x) varies inversely with x and g (x)=0.2 when x = 0.1. what is g (x) when x = 1.6? 0.0125 0.032 0.02 0.06

Answer : 0.0125

Suppose that g (x) varies inversely with x and g (x)=0.2 when x = 0.1.

If x varies inversely with y then y=k/x

Where k is constant of proportionality

g (x) varies inversely with x , so

g (x)=0.2 when x = 0.1

Plug in the values and solve for k

Multiply 0.1 on both sides

0.02 = k

so

Now we need to find g(x) when x= 1.6

Plug in 1.6 for x  and find out g(x) in the above equation

g(x)= 0.0125

step-by-step explanation:

subtract 7, so the answer is x < = 3, or c.