Brainliest! θ lies in quadrant ii . sinθ=4/7 what is the exact value of cosθ in simplified form?

sin theta = 4/7

theta = arcsin (4/7)

cos (arcsin (4/7)

if theta is in the second quadrant cos theta is negative (calculators only give the postive answer)

cos (arcsin (4/7)= - sqrt(33)/7

Choice B

cosθ = - .

Step-by-step explanation:

Given  : sinθ=.

To find : What is the exact value of cosθ in simplified  form .

Solution : We have given sinθ=.

By the trigonometric identity : .

Plug the value of sinθ=.

.

.

Subtracting  from both sides

.

.

.

Taking square root both sides

.

cosθ = ± .

θ lies in Quadrant II so,  cosθ = - .

Therefore, cosθ = - .

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2