Is this equal to 0?
6d^2+5d=1

6d² + 5d = 1

6(-1)² + 5(-1) = 1

(6 × 1) + (-5) = 1

6 - 5 = 1

1 = 1

So d equals -1

d = -1 and 1/6

6d² + 5d - 1 = 0

6d² + 6d - 1d - 1 = 0

6d(d+1) -1(d+1) = 0

(6d - 1)(d+1) = 0

d+1 = 0

  d = -1

and d also is

6d - 1 = 0  

   6d = 1

     d = 1/6

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a