What is the equation of a line that is perpendicular to y=5x-1 and passes through the point (2, -4)

y = -1/5x Hope this helps. I think this is the right answer.

Slope intercept form: y = mx + b

m = slope and b = y-intercept

From y = 5x - 1 we can already see that the slope is 5 since it is already in slope intercept form.

The slope of the perpendicular line is the negative reciprocal of the slope for the equation y = 5x - 1.

The negative reciprocal of 5 is -1/5.

So the incomplete equation for the perpendicular line is y = -1/5(x) + b

To find b plug in the x and y values from (2,-4) into the equation to get

         -4 = -1/5(2) + b

          b = -4 + 1/5(2)

          b = -4 + 2/5

          b = -18/5

The equation of the perpendicular line is y = -1/5(x) -18/5

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

$15 each

step-by-step explanation:

$45/3 children= $15 each