The product of two consecutive odd integers is 195. write an equation to model the situation. a) n(n + 1) = 195 b) n(n + 2) = 195 c) n(n + 3) = 195 d) (n + 1)(n + 2) = 195

You need the odd integers to be separated by 2. One will not work.

If n is odd, n + 1 will be even. You cannot get an exception to that. Try it.

1 is odd but 1 + 1 is even.

n and n + 3 produces 1 odd and 1 even. If n is odd then since 3 is odd when the two are added together, you get an even.  Again try it

n = 5

n + 3 = 8

C: is not the answer.

D can't work either. If n is odd then n + 2 will be odd but n + 1 is even.

The Answer is B.

n(n + 2) = 195

n^2 + 2n - 195 = 0

(n - 13)(n + 15)

n can be 13 and n + 2 can be 15

13 * 15 = 195

But here's something you may not know

n can be - 15 and then the other odd number would be - 13

show us the picture

step-by-step explanation:

show the !

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