Explain why 2x^2+18a=10 has no real number solutions

This equation does have real solutions contrary to your question. They are OR .

Step-by-step explanation:

In order to prove this has real number solutions, we simply need to use the quadratic formula. To do this, we first need to solve for 0.

2x^2 + 18x = 10

2x^2 + 18x - 10 = 0

Now that we have this and they are all factors of 2, we can divide everything by 2 for ease.

2x^2 + 18x - 10 = 0

x^2 + 9x - 5 = 0

Now we can use the quadratic equation to solve. Remember that A = 1 due to the coefficient of x^2, B = 9 as the coefficient of x and C = -5 as the constant.

OR

step-by-step explanation:

we don't have enough info to solve this