Rhoda’s conventional oven heats up at about 23 degrees per minute. after preheating the oven to 150 degrees, rhoda sets the temperature to 350 degrees to bake cupcakes. what is the time it will take for the oven to heat up from 150 degrees to 350 degrees?

The change in temperature from 150° to 350° is 200°. At the rate of 23°/min, it will take ...

... (200°)/(23°/min) = (200/23) min ≈ 8.70 min ≈ 8 min 42 sec

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

1/8 3/16 3/4

step-by-step explanation:

you put them as all the same denominator and multiply