What two consecutive integers does the square root 76 lie

if the integers are m and n, and they are consecutive, and n>m

m<√76<n

square everybody (assume m and n are positive)

m²<76<n²

so find the 2 square above and below

listing the squares, 1,4,9,16,25,36,49,64,81, and 76 is betwen 64 and 81

64<76<81

8²<76<9²

8<√76<9

it is between 8 and 9

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation: