The length of a rectangle is 3 inches more then it’s width if the perimeter is 42 inches find the dimensions of the rectangle

Hi!

The perimeter = 2*a + 2*b, where a is length and b is width.

In this case a = b + 3. Knowing that, we can calculate the dimensions:

42 = 2 * (b + 3) + 2*b

2b + 6 + 2b = 42

4b = 36

b = 9

a = 9 + 3 = 12

Hope this helps!

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation