The area of a rectanglular television screen is 1837 in^2. the width of the screen is 22.4 inches longer than the height. therefore, the quadratic equation that can be used to represent the area of the television screan is h(h+22.4)=1837. if you multiply, you then have the equivalent equation, h^2+22.4h=1837. complete the square to find the dimensions of the screen.

the equation second grade is

h^2+22,4h  =   1837

you  must subtract the second coefficient  and divide it by 2 ; 22,4 / 2 =  11,2, then  elevate it  to 2, ( 11,2 )^2 = 125,44

then

h^2+22,4h + 125,44 -125,44 = 1837

now √h^2 = h and  √125,44 = 11,2

(h+11,2)^2  -125,44 = 1837 ( dimensions of the screen )

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.