You have three $1 bills, four $5 bills, and two $10 bills in your wallet. you select a bill at random. without replacing the bill, you choose a second bill at random. what is p($10 then $1)?

Greetings!To find the first probability, you first find the amount of $10 bills and the total amount. Then you can put this into a fraction:

Now, do the same but for the total amount, be sure to remove 1 because you have not returned the first one picked. Now find the amount of $1 bills too:

Now you have two fractions of two consecutive events, now just simply multiply the two together:

x =

Now as both numbers are factors of 6, both can be divided by 6 to get a simplified probability:

÷ 6 =

So P($10 then $1) =
Hope this helps!

No a triangle cannot be formed because when you add the two smallest number together (which would be 11) the have to be bigger than the number it is "against" ( which would be 12)