Find the value of the variable such that the value of 5−a is 20 greater than the value of 6a−1

a = -2

We want (5-a) to be 20 more than (6a-1). Then we can write ...

... (5-a) = (6a-1) +20

If we add (a-19) to both sides, we get

... -14 = 7a

... -2 = a . . . . . divide by 7

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Comment on the graph

In the attached, we use the variable x, because this graphing calculator likes variables named x and y. We graph each expression and find the place where they both have the same value for the same value of x (the point of intersection). The value of the variable x at that point is -2, the solution we seek.

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step-by-step explanation: