Mathematics, 01.07.2019 09:00 kloeyknows7323
Divide the polynomials (6a³ + 14a² - 11a - 5) ÷ (3a + 1) = 6t³ - t² - 3t + 2 ÷ 2t - 1 = (4y³ - 7y + 3) ÷ (2y + 3) =
Answers: 1
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Divide the polynomials (6a³ + 14a² - 11a - 5) ÷ (3a + 1) = 6t³ - t² - 3t + 2 ÷ 2t - 1 = (4y³ - 7y...
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