Mathematics, 01.07.2019 07:00 jjbossgt
Aboat is 500 feet away from one dock and 600 feet away from another dock the angle between the two paths is 45. what is the approximate distance between the docks
Answers: 1
![\bf \textit{Law of Cosines}\\\\ c^2 = a^2+b^2-(2ab)cos(C)\implies c = \sqrt{a^2+b^2-(2ab)cos(C)} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} a=500\\ b=600\\ C=45^o \end{cases}\implies c=\sqrt{500^2+600^2-[2(500)(600)]cos(45^o)} \\\\\\ c=\sqrt{610000-600000\cdot \frac{\sqrt{2}}{2}}\implies c\approx \sqrt{185735.93}\implies c\approx 430.97](/tpl/images/0037/8309/1d94e.png)
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Aboat is 500 feet away from one dock and 600 feet away from another dock the angle between the two p...
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