On a coordinate grid, point a is located in the first quadrant. point b is located at (3, negative 1 over 2). point c is a reflection of point b across the y-axis. which graph shows these three points? a coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. point a is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the x-axis. a point b is plotted at 6 grid lines to the left of the y-axis and 1 grid line below the x-axis. a point c is plotted at 6 grid lines to the right of the y-axis and 1 grid line above the x-axis. a coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. point a is plotted 2 grid lines to the right of the y-axis and 4 grid lines above the x-axis. point b is plotted at 6 grid lines to the right of the y-axis and 1 grid line below the x-axis. point c is plotted at 6 grid lines to the right of the y-axis and 1 grid line above the x-axis. a coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. point a is plotted 2 grid lines to the right of the y-axis and 4 grid lines above the x-axis. point b is plotted at 6 grid lines to the right of the y-axis and 1 grid line below the x-axis. point c is plotted at 6 grid lines to the left of the y-axis and 1 grid line below the x-axis. a coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. point a is plotted 2 grid lines to the left of the y-axis and 4 grid lines above the x-axis. point b is plotted at 6 grid lines to the left of the y-axis and 1 grid line below the x-axis. point c is plotted at 6 grid lines to the left of the y-axis and 1 grid line above the x-axis.

A coordinate grid from negative 3 to positive 3 on both axes is drawn in increments of 1 over 2. Point A is plotted 2 grid lines to the right of the y-axis and 4 grid lines above the x-axis. Point B is plotted at 6 grid lines to the right of the y-axis and 1 grid line below the x-axis. Point C is plotted at 6 grid lines to the left of the y-axis and 1 grid line below the x-axis.

Each unit is represented by 2 grid lines. This means the coordinates of B (3, -1/2) will be 2×(3, -1/2) = (6, -1) grid lines. The reflection of B across the y-axis to get C will change the sign of the x-coordinate, so C is (-6, -1) in terms of grid lines. (Positive is above or right; negative is below or left.)

The above description is the only one that has the points in the right places.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation: